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How to encode a Javascript function in PHP? I want to encode the callback function with array
$options = array(
'title' => 'Title',
'fnCallback' => someCallback);
equivalent ini Javascript:
var options = {
'title': 'Title',
'fnCallback': someCallback };
I know my PHP code is wrong, how can I fix it?
307
To receive JSON string we can use the “php://input” along with the function file_get_contents() which helps us receive JSON data as a file and read it into a string. Later, we can use the json_decode() function to decode the JSON string.
In jQuery you can use the following code to encode the json: var data = {"key1":"value1", "key2":"value2","key3":"value3",...}; $. each(data,function(index,value)){ alert(index+" | "+value); });
php $data = '{ "name": "John Doe", "occupation": "gardener" }'; $a = json_decode($data, true); header('Content-type:text/html;charset=utf-8'); echo "{$a["name"]} is a {$a["occupation"]}"; The example transforms a JSON string into a PHP variable.
The json_encode() function is used to encode a value to JSON format.
Viola i solved my problem with Zend_JSON encoder
$options = array(
'title' => 'Title',
'fnCallback' => new Zend_Json_Expr('someCallback')
);
Zend_Json::encode(
$options,
false,
array('enableJsonExprFinder' => true));
JSON is for passing values around, they are not suitable for passing pieces of code.
You can, instead, pass a function name or other meaningful value and retrieve the right function to call from it on the JavaScript side.
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