I'm trying window.open
with a url with spaces:
var msg = 'Hello, world!';
var url = 'http://yoursite.com';
var link = 'http://www.twitter.com/share?text=' + msg + '&url=' + url;
window.open(link);
Running this code will open a new window with http://twitter.com/share?text=Hello,%2520world!&url=http://yoursite.com
.
What happens is that the space in msg is converted to %20, then the '%' is converted to %25. As a workaround, i added:
msg = msg.replace(/\s/g, '+');
But are there other chars i need to watch out for or is there a better workaround?
open() The open() method of the Window interface loads a specified resource into a new or existing browsing context (that is, a tab, a window, or an iframe) under a specified name.
open() method is used to open a new browser window or a new tab depending on the browser setting and the parameter values. Syntax: window. open(URL, name, specs, replace);
the pop up window must be able to return a value to the "parent". Typically this value is a Boolean but it could be any simple type (e.g.: string, int, etc.) solution must work even if the URL of the content is from different domain.
A space is assigned number 32, which is 20 in hexadecimal. When you see “%20,” it represents a space in an encoded URL, for example, http://www.example.com/products%20and%20services.html.
Try this instead:
var msg = encodeURIComponent('Hello, world!');
var url = encodeURIComponent('http://www.google.com');
var link = 'http://twitter.com/intent/tweet?text=' + msg + '&url=' + url;
window.open(link);
Note the different Twitter url and the encoding of the query string params.
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