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Having functions that are quite big and they are loading every time the page is loaded, would be better to write function foo(){ include(.../file_with_function's_code); return; } to minimize the size of the functions script? Or it doesn't matter because when a function is loaded (but not executed) also is loaded the content even if it is into an include? Thank you.
(Edit: my question is not about if it's possible or not)
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The include (or require ) statement takes all the text/code/markup that exists in the specified file and copies it into the file that uses the include statement. Including files is very useful when you want to include the same PHP, HTML, or text on multiple pages of a website.
include() Vs require() The only difference is that the include() statement generates a PHP alert but allows script execution to proceed if the file to be included cannot be found. At the same time, the require() statement generates a fatal error and terminates the script.
They are all ways of including files. Require means it needs it. Require_once means it will need it but only requires it once. Include means it will include a file but it doesn't need it to continue.
How failures in execution are handled with include() and require() functions? If the function require() cannot access to the file then it ends with a fatal error. However, the include() function gives a warning and the PHP script continues to execute.
While @Luceos answer is technically correct (the best kind of correct), it does not answer the question you asked, namely is doing this better, or do includes happen regardless of function calls?
I tested this in the most basic way (OP, why didn't you?):
<?php
echo "Testing...";
function doThing() {
include nonExistantFile.php;
}
//doThing();
echo "Done testing.";
Results:
if I call doThing(); I get a file not found warning.
If I comment out doThing();... there is no error! So you can save file load time by doing this.
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