php if statement html option value

Question

Suppose you have the following html select statement

<select>
<option value="Newest">Newest</option>
<option value="Best Sellers">Best Sellers</option>
<option value="Alphabetical">Alphabetical</option>
</select>

Now I want to run a php if elseif statement that says,

if (option value = newest) {
// Run this
}
elseif ( option value = best sellers ) {
// Run this
}

etc. But I don't know what to put inside the if elseif statement. In other words instead of 'option value = newest' (which I know is incorrect), what can I put there so that if newest is selected it will execute the if statement, or if best sellers is selected it will execute the elseif statement?

Answer 1

Give name to your select.

<select name="selectedValue">
<option value="Newest">Newest</option>
<option value="Best Sellers">Best Sellers</option>
<option value="Alphabetical">Alphabetical</option>
</select>

in your PHP, you will do:

$_POST['selectedValue'];

if I were you, I would prefer a switch-case incase, there are more than 2 conditions.

Example:

switch($_POST['selectedValue']){
case 'Newest':
    // do Something for Newest
break;
case 'Best Sellers':
    // do Something for Best seller
break;
case 'Alphabetical':
    // do Something for Alphabetical
break;
default:
    // Something went wrong or form has been tampered.
}

Answer 2

First put a name on your select:

<select name="demo">
<option value="Newest">Newest</option>
<option value="Best Sellers">Best Sellers</option>
<option value="Alphabetical">Alphabetical</option>
</select>

Then

if ($_POST['demo'] === 'Newest') {
// Run this
}
elseif ( $_POST['demo'] === 'Best Sellers' ) {
// Run this
}

or

switch($_POST['demo']){
    case 'Newest' : 
        //some code;
        break;
    case 'Best Sellers':
        //some code;
        break;
    default:
        //some code if the post doesn't match anything
}