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I have this example shell script:
echo /$1/ So I may call
$ . ./script 5 # output: /5/ I want to pipe the script into sh(ell), but can I pass the arg too ?
cat script | sh # output: // 
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Arguments can be passed to the script when it is executed, by writing them as a space-delimited list following the script file name. Inside the script, the $1 variable references the first argument in the command line, $2 the second argument and so forth. The variable $0 references to the current script.
The pipe character | is used to connect the output from one command to the input of another. > is used to redirect standard output to a file. Try it in the shell-lesson-data/exercise-data/proteins directory!
You can pass the arguments to any bash script when it is executed. There are several simple and useful ways to pass arguments in a bash script. In this article guide, we will let you know about some very easy ways to pass and use arguments in your bash scripts.
bash [filename] runs the commands saved in a file. $@ refers to all of a shell script's command-line arguments. $1 , $2 , etc., refer to the first command-line argument, the second command-line argument, etc. Place variables in quotes if the values might have spaces in them.
You can pass arguments to the shell using the -s option:
cat script | bash -s 5 Use bash -s -- <args>
e.g, install google cloud sdk
~ curl https://sdk.cloud.google.com | bash -s -- --disable-prompts
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