Parsing variables from config file in Bash

Question

Having the following content in a file:

VARIABLE1="Value1" VARIABLE2="Value2" VARIABLE3="Value3" 

I need a script that outputs the following:

Content of VARIABLE1 is Value1 Content of VARIABLE2 is Value2 Content of VARIABLE3 is Value3 

Any ideas?

Answer 1

Since your config file is a valid shell script, you can source it into your current shell:

. config_file echo "Content of VARIABLE1 is $VARIABLE1" echo "Content of VARIABLE2 is $VARIABLE2" echo "Content of VARIABLE3 is $VARIABLE3" 

Slightly DRYer, but trickier

. config_file for var in VARIABLE1 VARIABLE2 VARIABLE3; do     echo "Content of $var is ${!var}" done