I'm trying to parse a string with a TStringList:
sl:=TStringList.Create;
try
sl.Text:=aString;
FFirstRow:=sl[0];
FSecondRow:=sl[1];
finally
sl.Free;
end;
If aString:='aa'+#13#10+'bb' or aString:='aa'+sLineBreak+'bb' then FFirstRow is aa and FSecondRow is bb. But if aString:='aa\nbb'then FFirstRow gets the whole string (and there is no second row). How do I parse the string with \n as a delimiter?
I tried sl.Delimiter:=Char(13) (and sl.DelimitedText:=aString).
You can just change the string that is treated as the line break in a TStringList:
sl := TStringList.Create;
try
sl.LineBreak := '\n';
sl.Text := aString;
FFirstRow := sl[0];
FSecondRow := sl[1];
finally
sl.Free;
end;
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With