Parsing and Printing $PATH Using Unix

Question

I've placed my PATH in a text file and would like to print each path on a newline using a simple command in UNIX.

I've found a long way to do it that goes like this...

cat Path.txt | awk -F\; '{print $1"\n", $2"\n", ... }'

This however seems inefficient so I know there must be a way to quickly print out my results on new lines each time without having to manually call each field separated by the delimiter.

Answer 1

Yet another way:

echo $PATH | tr : '\n'

or:

tr : '\n' <Path.txt

Answer 2

The tr solution is the right one but if you were going to use awk then there'd be no need for a loop:

$ echo "$PATH"
/usr/local/bin:/usr/bin:/cygdrive/c/winnt/system32:/cygdrive/c/winnt

$ echo "$PATH" | awk -F: -v OFS="\n" '$1=$1'
/usr/local/bin
/usr/bin
/cygdrive/c/winnt/system32
/cygdrive/c/winnt