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Parallel.For step size

does anyone know if there's any overload that would allow me to specify a step size in a Parallel.For loop? Samples in either c# or VB.Net would be great.

Thanks, Gonzalo

like image 347
Gonzalo Avatar asked Aug 22 '11 01:08

Gonzalo


1 Answers

Google for "enumerable.range step" and you should be able to come upon alternate implementations of Enumerable.Range that provide stepped ranges. Then you can just do a

Parallel.ForEach(BetterEnumerable.SteppedRange(fromInclusive, toExclusive, step), ...)

If google isn't working, implementation should be something like this:

public static class BetterEnumerable {
    public static IEnumerable<int> SteppedRange(int fromInclusive, int toExclusive, int step) {
        for (var i = fromInclusive; i < toExclusive; i += step) {
            yield return i;
        }
    }
}

Alternately if "yield return" gives one the heebie jeebies, you can always just create a regular old list in-place:

var list = new List<int>();
for (int i = fromInclusive; i < toExclusive; i += step) {
    list.Add(i);
}
Parallel.ForEach(list, ...);

This should be easily translatable to VB if that's a requirement.

like image 153
Dax Fohl Avatar answered Sep 20 '22 19:09

Dax Fohl