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Calculating SHA-1 hashes in Java and C#

Tags:

java

c#

hash

sha1

Calculating SHA-1 hashes in Java and C#

I'm trying to replicate the logic of a Java application within a C# application. Part of this involves generating an SHA-1 hash of a password. Unfortunately I can't get the same results from Java and C#.

C# Output  : 64  0a  b2 ba e0 7b  ed c4 c1 63  f6 79  a7 46  f7 ab 7f  b5 d1 fa
Java Output: 164 10a b2 ba e0 17b ed c4 c1 163 f6 179 a7 146 f7 ab 17f b5 d1 fa 

To try and figure out what is happening I've been using the Debugger in Eclipse and Visual Studio.

1. Check values of byte[] key:

    Java: { 84, 101, 115, 116 }
    C#  : { 84, 101, 115, 116 }

2. Check value of byte[] hash:

    Java: { 100 10 -78 -70 -32 123 ... }
    C#  : { 100 10  78 186 224 123 ... }

I've read the other posts on this topic, which largely refer to input string encoding, but these don't seem to have helped me. My guess would be that this is something to do with signed vs. unsigned bytes but I'm not making much progress down this track. Any help will be greatly appreciated.

Thanks,

Karle


Java Version:

public void testHash() {

    String password = "Test";

    byte[] key = password.getBytes();

    MessageDigest md = MessageDigest.getInstance("SHA-1");

    byte[] hash = md.digest(key);

    String result = "";
    for ( byte b : hash ) {
        result += Integer.toHexString(b + 256) + " ";
    }

    System.out.println(result);

}

C# Version:

public void testHash() {

    String password = "Test";

    byte[] key = System.Text.Encoding.Default.GetBytes(password);

    SHA1 sha1 = SHA1Managed.Create();

    byte[] hash = sha1.ComputeHash(key);

    String result;
    foreach ( byte b in hash ) {
        result += Convert.ToInt32(b).ToString("x2") + " ";
    }

    Console.WriteLine(result);

}
like image 697
Karle Avatar asked Jul 27 '11 11:07

Karle


Video Answer


1 Answers

In the Java version, do not use b + 256; instead, use b & 255. The SHA-1 part is fine, this is just a matter of printing the output. Java's "byte" type is signed: it returns values between -128 and 127. To get the corresponding unsigned value, you must add 256 only if the value is negative.

A bitwise AND with 255 (that's what "& 255" does) operates the proper conversion, which, at the binary level, is truncation of the value to its 8 least significant bits.

like image 185
Thomas Pornin Avatar answered Sep 21 '22 07:09

Thomas Pornin