Order of calling constructors case of inheritance in c# [duplicate]

Question

I was just reading Inheritance in C# in which i came across the Constructors and was written that constructors are executed in order of derivation. What does it mean?That base class constructor will be called first or Derived class.

Answer 1

The base class constructor will be called first. You can test this pretty easily yourself:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace DerivationTest
{
    class Program
    {
        public class Thing
        {
            public Thing()
            {
                Console.WriteLine("Thing");
            }
        }

        public class ThingChild : Thing
        {
            public ThingChild()
            {
                Console.WriteLine("ThingChild");
            }
        }

        static void Main(string[] args)
        {
            var tc = new ThingChild();
            Console.ReadLine();
        }
    }
}

Answer 2

A base class Constructor is called first.Refer to the following example

// Demonstrate when constructors are called.
using System;

// Create a base class.
class A {
    public A() {
        Console.WriteLine("Constructing A.");
    }
}

// Create a class derived from A.
class B : A {
    public B() {
        Console.WriteLine("Constructing B.");
    }
}

// Create a class derived from B.
class C : B {
    public C() {
        Console.WriteLine("Constructing C.");
    }
}

class OrderOfConstruction {
    static void Main() {
        C c = new C();
    }
}

The output from this program is shown here:

Constructing A.
Constructing B.
Constructing C.