I am trying to open from my keyboard extension. I am having custom keyboard and I have add that keyboard from setting. On my custom keyboard there is one button “Show More”, and I want to open my app on this button click.
So I have tried following code :
let context = NSExtensionContext()
context.open(url! as URL, completionHandler: nil)
var responder = self as UIResponder?
while (responder != nil) {
if responder?.responds(to: Selector("openURL:")) == true {
responder?.perform(Selector("openURL:"), with: url)
}
responder = responder!.next
}
It is working successfully, but as we know in swift Selector("method_name:")
is deprecated and use #selector(classname.methodname(_:))
instead so it is giving warning. And I want to solve that warning. So I have tried as Xcode automatically suggested :
if responder?.responds(to: #selector(UIApplication.openURL(_:))) == true {
responder?.perform(#selector(UIApplication.openURL(_:)), with: url)
}
Also tried :
if responder?.responds(to: #selector(NSExtensionContext.open(_:))) == true {
responder?.perform(#selector(NSExtensionContext.open(_:)), with: url)
}
I have also tried others possible ways, but no luck. If anyone know how to do, please let me know.
I referred this link, Julio Bailon’s answer :
openURL not work in Action Extension
Swift 5.0:
Open Info.plist of hosting app.
Go to Keyboard App:
Add following code properly:
@objc func openURL(_ url: URL) {
return
}
func openApp(_ urlstring:String) {
var responder: UIResponder? = self as UIResponder
let selector = #selector(openURL(_:))
while responder != nil {
if responder!.responds(to: selector) && responder != self {
responder!.perform(selector, with: URL(string: urlstring)!)
return
}
responder = responder?.next
}
}
Call : openApp ("yourappname://your bundle id")
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