Undefined Index in PHP is a Notice generated by the language. The simplest way to ignore such a notice is to ask PHP to stop generating such notices. You can either add a small line of code at the top of the PHP page or edit the field error_reporting in the php. ini file.
The error can be avoided by using the isset() method. This method will check whether the declared array key has null value or not. If it does it returns false else it returns true for all cases. This type of error occurs with arrays when we use the key of an array, which is not set.
When using them, you might encounter an error called “Notice: Undefined Index”. This error means that within your code, there is a variable or constant that has no value assigned to it. But you may be trying to use the values obtained through the user form in your PHP code.
Notice Undefined Index in PHP is an error which occurs when we try to access the value or variable which does not even exist in reality. Undefined Index is the usual error that comes up when we try to access the variable which does not persist.
From the vast wisdom of the PHP Manual:
Relying on the default value of an uninitialized variable is problematic in the case of including one file into another which uses the same variable name. It is also a major security risk with register_globals turned on. E_NOTICE level error is issued in case of working with uninitialized variables, however not in the case of appending elements to the uninitialized array. isset() language construct can be used to detect if a variable has been already initialized. Additionally and more ideal is the solution of empty() since it does not generate a warning or error message if the variable is not initialized.
From PHP documentation:
No warning is generated if the variable does not exist. That means empty() is essentially the concise equivalent to !isset($var) || $var == false.
This means that you could use only empty()
to determine if the variable is set, and in addition it checks the variable against the following, 0
, 0.0
, ""
, "0"
, null
, false
or []
.
Example:
$o = [];
@$var = ["",0,null,1,2,3,$foo,$o['myIndex']];
array_walk($var, function($v) {
echo (!isset($v) || $v == false) ? 'true ' : 'false';
echo ' ' . (empty($v) ? 'true' : 'false');
echo "\n";
});
Test the above snippet in the 3v4l.org online PHP editor
Although PHP does not require a variable declaration, it does recommend it in order to avoid some security vulnerabilities or bugs where one would forget to give a value to a variable that will be used later in the script. What PHP does in the case of undeclared variables is issue a very low level error, E_NOTICE
, one that is not even reported by default, but the Manual advises to allow during development.
Ways to deal with the issue:
Recommended: Declare your variables, for example when you try to append a string to an undefined variable. Or use isset()
/ !empty()
to check if they are declared before referencing them, as in:
//Initializing variable
$value = ""; //Initialization value; Examples
//"" When you want to append stuff later
//0 When you want to add numbers later
//isset()
$value = isset($_POST['value']) ? $_POST['value'] : '';
//empty()
$value = !empty($_POST['value']) ? $_POST['value'] : '';
This has become much cleaner as of PHP 7.0, now you can use the null coalesce operator:
// Null coalesce operator - No need to explicitly initialize the variable.
$value = $_POST['value'] ?? '';
Set a custom error handler for E_NOTICE and redirect the messages away from the standard output (maybe to a log file):
set_error_handler('myHandlerForMinorErrors', E_NOTICE | E_STRICT)
Disable E_NOTICE from reporting. A quick way to exclude just E_NOTICE
is:
error_reporting( error_reporting() & ~E_NOTICE )
Suppress the error with the @ operator.
Note: It's strongly recommended to implement just point 1.
This notice appears when you (or PHP) try to access an undefined index of an array.
Ways to deal with the issue:
Check if the index exists before you access it. For this you can use isset()
or array_key_exists()
:
//isset()
$value = isset($array['my_index']) ? $array['my_index'] : '';
//array_key_exists()
$value = array_key_exists('my_index', $array) ? $array['my_index'] : '';
The language construct list()
may generate this when it attempts to access an array index that does not exist:
list($a, $b) = array(0 => 'a');
//or
list($one, $two) = explode(',', 'test string');
Two variables are used to access two array elements, however there is only one array element, index 0
, so this will generate:
Notice: Undefined offset: 1
$_POST
/ $_GET
/ $_SESSION
variableThe notices above appear often when working with $_POST
, $_GET
or $_SESSION
. For $_POST
and $_GET
you just have to check if the index exists or not before you use them. For $_SESSION
you have to make sure you have the session started with session_start()
and that the index also exists.
Also note that all 3 variables are superglobals and are uppercase.
Related:
Try these
Q1: this notice means $varname is not defined at current scope of the script.
Q2: Use of isset(), empty() conditions before using any suspicious variable works well.
// recommended solution for recent PHP versions
$user_name = $_SESSION['user_name'] ?? '';
// pre-7 PHP versions
$user_name = '';
if (!empty($_SESSION['user_name'])) {
$user_name = $_SESSION['user_name'];
}
Or, as a quick and dirty solution:
// not the best solution, but works
// in your php setting use, it helps hiding site wide notices
error_reporting(E_ALL ^ E_NOTICE);
Note about sessions:
When using sessions, session_start();
is required to be placed inside all files using sessions.
http://php.net/manual/en/features.sessions.php
@
operator
For undesired and redundant notices, one could use the dedicated @
operator to »hide« undefined variable/index messages.
$var = @($_GET["optional_param"]);
isset?:
or ??
super-supression however. Notices still can get logged. And one may resurrect @
-hidden notices with: set_error_handler("var_dump");
if (isset($_POST["shubmit"]))
in your initial code.@
or isset
only after verifying functionality.Fix the cause first. Not the notices.
@
is mainly acceptable for $_GET
/$_POST
input parameters, specifically if they're optional.And since this covers the majority of such questions, let's expand on the most common causes:
$_GET
/ $_POST
/ $_REQUEST
undefined inputFirst thing you do when encountering an undefined index/offset, is check for typos:$count = $_GET["whatnow?"];
Secondly, if the notice doesn't have an obvious cause, use var_dump
or print_r
to verify all input arrays for their curent content:
var_dump($_GET);
var_dump($_POST);
//print_r($_REQUEST);
Both will reveal if your script was invoked with the right or any parameters at all.
Alternativey or additionally use your browser devtools (F12) and inspect the network tab for requests and parameters:
POST parameters and GET input will be be shown separately.
For $_GET
parameters you can also peek at the QUERY_STRING
in
print_r($_SERVER);
PHP has some rules to coalesce non-standard parameter names into the superglobals. Apache might do some rewriting as well.
You can also look at supplied raw $_COOKIES
and other HTTP request headers that way.
More obviously look at your browser address bar for GET parameters:
http://example.org/script.php?id=5&sort=desc
The name=value
pairs after the ?
question mark are your query (GET) parameters. Thus this URL could only possibly yield $_GET["id"]
and $_GET["sort"]
.
Finally check your <form>
and <input>
declarations, if you expect a parameter but receive none.
<input name=FOO>
id=
or title=
attribute does not suffice.method=POST
form ought to populate $_POST
.method=GET
(or leaving it out) would yield $_GET
variables.action=script.php?get=param
via $_GET and the remaining method=POST
fields in $_POST alongside.$_REQUEST['vars']
again, which mashes GET and POST params.If you are employing mod_rewrite, then you should check both the access.log
as well as enable the RewriteLog
to figure out absent parameters.
$_FILES
$_FILES["formname"]
.enctype=multipart/form-data
method=POST
in your <form>
declaration.$_COOKIE
$_COOKIE
array is never populated right after setcookie()
, but only on any followup HTTP request.Generally because of "bad programming", and a possibility for mistakes now or later.
if (isset($varname))
, before using itIt means you are testing, evaluating, or printing a variable that you have not yet assigned anything to. It means you either have a typo, or you need to check that the variable was initialized to something first. Check your logic paths, it may be set in one path but not in another.
I didn't want to disable notice because it's helpful, but I wanted to avoid too much typing.
My solution was this function:
function ifexists($varname)
{
return(isset($$varname) ? $varname : null);
}
So if I want to reference to $name and echo if exists, I simply write:
<?= ifexists('name') ?>
For array elements:
function ifexistsidx($var,$index)
{
return(isset($var[$index]) ? $var[$index] : null);
}
In a page if I want to refer to $_REQUEST['name']:
<?= ifexistsidx($_REQUEST, 'name') ?>
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