I am trying to select data from a MySQL table, but I get one of the following error messages:
mysql_fetch_array() expects parameter 1 to be resource, boolean given
This is my code:
$username = $_POST['username']; $password = $_POST['password']; $result = mysql_query('SELECT * FROM Users WHERE UserName LIKE $username'); while($row = mysql_fetch_array($result)) { echo $row['FirstName']; }
mysql_fetch_array is a PHP function that will allow you to access data stored in the result returned from the TRUE mysql_query if u want to know what is returned when you used the mysql_query function to query a Mysql database. It is not something that you can directly manipulate. Syntax.
mysqli_fetch_array() is an extended version of the mysqli_fetch_row() function. In addition to storing the data in the numeric indices of the result array, the mysqli_fetch_array() function can also store the data in associative indices, using the field names of the result set as keys.
Difference: mysql_fetch_assoc() will always assing a non-secuencial key (like "color" and not a number). mysql_fetch_array() will assing a number key if there are not "word" key (0 and not "color" if there are not "color") but, you can choose to assing of key with a parameter...
The fetch_assoc() / mysqli_fetch_assoc() function fetches a result row as an associative array. Note: Fieldnames returned from this function are case-sensitive.
A query may fail for various reasons in which case both the mysql_* and the mysqli extension will return false
from their respective query functions/methods. You need to test for that error condition and handle it accordingly.
mysql_* extension:
NOTE The mysql_ functions are deprecated and have been removed in php version 7.
Check $result
before passing it to mysql_fetch_array
. You'll find that it's false
because the query failed. See the mysql_query
documentation for possible return values and suggestions for how to deal with them.
$username = mysql_real_escape_string($_POST['username']); $password = $_POST['password']; $result = mysql_query("SELECT * FROM Users WHERE UserName LIKE '$username'"); if($result === FALSE) { die(mysql_error()); // TODO: better error handling } while($row = mysql_fetch_array($result)) { echo $row['FirstName']; }
mysqli extension
procedural style:
$username = mysqli_real_escape_string($mysqli, $_POST['username']); $result = mysqli_query($mysqli, "SELECT * FROM Users WHERE UserName LIKE '$username'"); // mysqli_query returns false if something went wrong with the query if($result === FALSE) { yourErrorHandler(mysqli_error($mysqli)); } else { // as of php 5.4 mysqli_result implements Traversable, so you can use it with foreach foreach( $result as $row ) { ...
oo-style:
$username = $mysqli->escape_string($_POST['username']); $result = $mysqli->query("SELECT * FROM Users WHERE UserName LIKE '$username'"); if($result === FALSE) { yourErrorHandler($mysqli->error); // or $mysqli->error_list } else { // as of php 5.4 mysqli_result implements Traversable, so you can use it with foreach foreach( $result as $row ) { ...
using a prepared statement:
$stmt = $mysqli->prepare('SELECT * FROM Users WHERE UserName LIKE ?'); if ( !$stmt ) { yourErrorHandler($mysqli->error); // or $mysqli->error_list } else if ( !$stmt->bind_param('s', $_POST['username']) ) { yourErrorHandler($stmt->error); // or $stmt->error_list } else if ( !$stmt->execute() ) { yourErrorHandler($stmt->error); // or $stmt->error_list } else { $result = $stmt->get_result(); // as of php 5.4 mysqli_result implements Traversable, so you can use it with foreach foreach( $result as $row ) { ...
These examples only illustrate what should be done (error handling), not how to do it. Production code shouldn't use or die
when outputting HTML, else it will (at the very least) generate invalid HTML. Also, database error messages shouldn't be displayed to non-admin users, as it discloses too much information.
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