I have a json array like this:
[
{
"variable1":"example",
"variable2": "example1\nexample2\nexample3"
},
{
"variable1":"exampleLast\n",
"variable2": "example1\nexample2\nexample3"
}
]
I am trying to parse this json a List in Flutter.
List posts = json.decode(response.data);
When I tried using 'dart:convert' it gives error FormatException... Control character in string (at line...)
.
I found this issue on Github but I can not find solution.
https://github.com/dart-lang/convert/issues/10
You can do the following: String receivedJson = "... Your JSON string ...."; List<dynamic> list = json. decode(receivedJson); Fact fact = Fact.
The deep_pick package simplifies JSON parsing with a type-safe API. Once installed, we can use it to get the value we want without manual casts: deep_pick offers a variety of flexible APIs that we can use to parse primitive types, lists, maps, DateTime objects, and more.
Dart has built in support for parsing json. Given a String you can use the dart:convert library and convert the Json (if valid json) to a Map with string keys and dynamic objects. You can parse json directly and use the map or you can parse it and put it into a typed object so that your data has more structure and it's easier to maintain.
You can parse json directly and use the map or you can parse it and put it into a typed object so that your data has more structure and it's easier to maintain. So the way you access your parsed data is by using key index on the returned map.
And if you need to parse large JSON data, you should do so in a separate isolate for best performance. This article covers all the details: I launched a brand new course where you will learn about state management, app architecture, navigation, testing, and much more:
You just need to replace single slash to double slash and everything goes fine.
String replaced = string.replaceAll(r'\', r'\\');
Just replace the single backslash(\n) with double backslash(\\n) in your code:
[{
"variable1": "example",
"variable2": "example1\\nexample2\\nexample3"
},
{
"variable1": "exampleLast\\n",
"variable2": "example1\\nexample2\\nexample3"
}]
You need to escape the \ in your string (turning it into a double-), otherwise it will become a newline in the JSON source, not the JSON data.
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