multiple parallel async calls with await

Question

As far as I know, when runtime comes across the statement below it wraps the rest of the function as a callback to the method which is invoked asynchronously (someCall() in this example). In this case anotherCall() will be executed as a callback to someCall():

    await someCall();     await anotherCall(); 

I wonder if it is possible to make runtime perform like this: call someCall() in async fashion and return immediately to the calling thread, then invoke anotherCall() similarly (without waiting someCall to complete). Because I need these two methods to run asynchronously and suppose these calls are just fire and forget calls.

Is it possible to implement this scenario using just async and await (not using old begin/end mechanism)?

Answer 1

The async/await includes a few operators to help with parallel composition, such as WhenAll and WhenAny.

var taskA = someCall(); // Note: no await var taskB = anotherCall(); // Note: no await  // Wait for both tasks to complete. await Task.WhenAll(taskA, taskB);  // Retrieve the results. var resultA = taskA.Result; var resultB = taskB.Result; 

Answer 2

The simplest way is probably to do this:

var taskA = someCall(); var taskB = someOtherCall(); await taskA; await taskB; 

This is especially nice if you want the result values:

var result = await taskA + await taskB; 

so you don't need to do taskA.Result.

TaskEx.WhenAll might be faster than two awaits after each other. i don't know since I haven't done performance investigation on that, but unless you see a problem I think the two consecutive awaits reads better, especially if you ewant the result values.