Most efficient way to make the first character of a String lower case?

Question

What is the most efficient way to make the first character of a String lower case?

I can think of a number of ways to do this:

Using charAt() with substring()

String input   = "SomeInputString"; String output  = Character.toLowerCase(input.charAt(0)) +                    (input.length() > 1 ? input.substring(1) : ""); 

Or using a char array

 String input  = "SomeInputString";  char c[]      = input.toCharArray();  c[0]          = Character.toLowerCase(c[0]);  String output = new String(c); 

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I am sure there are many other great ways to achieve this. What do you recommend?

Answer 1

I tested the promising approaches using JMH. Full benchmark code.

Assumption during the tests (to avoid checking the corner cases every time): the input String length is always greater than 1.

Results

Benchmark           Mode  Cnt         Score        Error  Units MyBenchmark.test1  thrpt   20  10463220.493 ± 288805.068  ops/s MyBenchmark.test2  thrpt   20  14730158.709 ± 530444.444  ops/s MyBenchmark.test3  thrpt   20  16079551.751 ±  56884.357  ops/s MyBenchmark.test4  thrpt   20   9762578.446 ± 584316.582  ops/s MyBenchmark.test5  thrpt   20   6093216.066 ± 180062.872  ops/s MyBenchmark.test6  thrpt   20   2104102.578 ±  18705.805  ops/s 

The score are operations per second, the more the better.

Tests

1. test1 was first Andy's and Hllink's approach:

   string = Character.toLowerCase(string.charAt(0)) + string.substring(1); 

2. test2 was second Andy's approach. It is also Introspector.decapitalize() suggested by Daniel, but without two if statements. First if was removed because of the testing assumption. The second one was removed, because it was violating correctness (i.e. input "HI" would return "HI"). This was almost the fastest.

   char c[] = string.toCharArray(); c[0] = Character.toLowerCase(c[0]); string = new String(c); 

3. test3 was a modification of test2, but instead of Character.toLowerCase(), I was adding 32, which works correctly if and only if the string is in ASCII. This was the fastest. c[0] |= ' ' from Mike's comment gave the same performance.

   char c[] = string.toCharArray(); c[0] += 32; string = new String(c); 

4. test4 used StringBuilder.

   StringBuilder sb = new StringBuilder(string); sb.setCharAt(0, Character.toLowerCase(sb.charAt(0))); string = sb.toString(); 

5. test5 used two substring() calls.

   string = string.substring(0, 1).toLowerCase() + string.substring(1); 

6. test6 uses reflection to change char value[] directly in String. This was the slowest.

   try {     Field field = String.class.getDeclaredField("value");     field.setAccessible(true);     char[] value = (char[]) field.get(string);     value[0] = Character.toLowerCase(value[0]); } catch (IllegalAccessException e) {     e.printStackTrace(); } catch (NoSuchFieldException e) {     e.printStackTrace(); } 

Conclusions

If the String length is always greater than 0, use test2.

If not, we have to check the corner cases:

public static String decapitalize(String string) {     if (string == null || string.length() == 0) {         return string;     }      char c[] = string.toCharArray();     c[0] = Character.toLowerCase(c[0]);      return new String(c); } 

If you are sure that your text will be always in ASCII and you are looking for extreme performance because you found this code in the bottleneck, use test3.

Answer 2

I came across a nice alternative if you don't want to use a third-party library:

import java.beans.Introspector;  Assert.assertEquals("someInputString", Introspector.decapitalize("SomeInputString"));