So I know about String#codePointAt(int)
, but it's indexed by the char
offset, not by the codepoint offset.
I'm thinking about trying something like:
String#charAt(int)
to get the char
at an indexchar
is in the high-surrogates range String#codePointAt(int)
to get the codepoint, and increment the index by 2char
value as the codepoint, and increment the index by 1But my concerns are
char
values or oneAccording to section 3.3 of the Java Language Specification (JLS) a unicode escape consists of a backslash character (\) followed by one or more 'u' characters and four hexadecimal digits. So for example \u000A will be treated as a line feed.
Unicode is an international standard of character encoding which has the capability of representing a majority of written languages all over the globe. Unicode uses hexadecimal to represent a character. Unicode is a 16-bit character encoding system. The lowest value is \u0000 and the highest value is \uFFFF.
Unicode sequences can be used everywhere in Java code. As long as it contains Unicode characters, it can be used as an identifier. You may use Unicode to convey comments, ids, character content, and string literals, as well as other information.
Yes, Java uses a UTF-16-esque encoding for internal representations of Strings, and, yes, it encodes characters outside the Basic Multilingual Plane (BMP) using the surrogacy scheme.
If you know you'll be dealing with characters outside the BMP, then here is the canonical way to iterate over the characters of a Java String:
final int length = s.length(); for (int offset = 0; offset < length; ) { final int codepoint = s.codePointAt(offset); // do something with the codepoint offset += Character.charCount(codepoint); }
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