dates have multiple date objects. We spread the dates array into Math. max and Math. min , which will convert the dates entries into UNIX timestamps, which are numbers.
To find the minimum value present in a given array, we can use the Math. min() function in JavaScript. This function returns the minimum value present in a given array. For example, let's define an array with some random values and find its minimum value using the Math.
Code is tested with IE,FF,Chrome and works properly:
var dates=[];
dates.push(new Date("2011/06/25"))
dates.push(new Date("2011/06/26"))
dates.push(new Date("2011/06/27"))
dates.push(new Date("2011/06/28"))
var maxDate=new Date(Math.max.apply(null,dates));
var minDate=new Date(Math.min.apply(null,dates));
Something like:
var min = dates.reduce(function (a, b) { return a < b ? a : b; });
var max = dates.reduce(function (a, b) { return a > b ? a : b; });
Tested on Chrome 15.0.854.0 dev
_.min
and _.max
work on arrays of dates; use those if you're using Lodash or Underscore, and consider using Lodash (which provides many utility functions like these) if you're not already.
For example,
_.min([
new Date('2015-05-08T00:07:19Z'),
new Date('2015-04-08T00:07:19Z'),
new Date('2015-06-08T00:07:19Z')
])
will return the second date in the array (because it is the earliest).
Same as apply, now with spread :
const maxDate = new Date(Math.max(...dates));
(could be a comment on best answer)
Since dates are converted to UNIX epoch (numbers), you can use Math.max/min to find those:
var maxDate = Math.max.apply(null, dates)
// convert back to date object
maxDate = new Date(maxDate)
(tested in chrome only, but should work in most browsers)
**Use Spread Operators| ES6 **
let datesVar = [ 2017-10-26T03:37:10.876Z,
2017-10-27T03:37:10.876Z,
2017-10-23T03:37:10.876Z,
2015-10-23T03:37:10.876Z ]
Math.min(...datesVar);
That will give the minimum date from the array.
Its shorthand Math.min.apply(null, ArrayOfdates);
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