Generally, we can define __str__
method to make str(obj)
return what we want.
But now I want to define my Model object to return a default JSON string when using json.dumps(obj)
.
Is there any nice way for me to declare a method in the class to do this?
class MyClass:
...
def __json__(self):
return {'name': self.name, 'age': self.age}
obj = MyClass()
json.dumps(obj) # returns the same as json.dumps(obj.__json__)
If you only need Python -> JSON, it's simple to write a JSONEncoder class that calls such a method for any object:
class AutoJSONEncoder(JSONEncoder):
def default(self, obj):
try:
return obj._json()
except AttributeError:
return JSONEncoder.default(self, obj)
You can then use the class directly AutoJSONEncoder().encode(obj)
or through the dumps
interface json.dumps(obj, cls=AutoJSONEncoder)
.
The reverse direction requires at least a list of classes for which to call a _fromjson
method.
(Note: __foo__
names are reserved so you shouldn't define them for your own purposes. __bar
invokes name mangling, which probably isn't what you want.)
import json
class MyEncoder(json.JSONEncoder):
"""
JSONEncoder subclass that leverages an object's `__json__()` method,
if available, to obtain its default JSON representation.
"""
def default(self, obj):
if hasattr(obj, '__json__'):
return obj.__json__()
return json.JSONEncoder.default(self, obj)
class MyClass(object):
name = 'John'
age = 30
def __json__(self):
return {'name': self.name, 'age': self.age}
>>> json.dumps(MyClass(), cls=MyEncoder)
{"age": 30, "name": "John"}
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