I have a dataframe that has two rows:
| code | name | v1 | v2 | v3 | v4 |
|------|-------|----|----|----|----|
| 345 | Yemen | NA | 2 | 3 | NA |
| 346 | Yemen | 4 | NA | NA | 5 |
Is there an easy way to merge these two rows? What if I rename "345" in "346", would that make things easier?
Use the left_join Function to Merge Two R Data Frames With Different Number of Rows. left_join is another method from the dplyr package. It takes arguments similar to the full_join function, but left_join extracts all rows from the first data frame and all columns from both of them.
To merge two data frames (datasets) horizontally, use the merge() function in the R language. To bind or combine rows in R, use the rbind() function. The rbind() stands for row binding.
Key PointsPandas' merge and concat can be used to combine subsets of a DataFrame, or even data from different files. join function combines DataFrames based on index or column. Joining two DataFrames can be done in multiple ways (left, right, and inner) depending on what data must be in the final DataFrame.
First, select the rows you want to merge then open the Home tab and expand Merge & Centre. From these options select Merge Cells. After selecting Merge Cells it will pop up a message which values it is going to keep. Then click on OK.
You can use aggregate
. Assuming that you want to merge rows with identical values in column name
:
aggregate(x=DF[c("v1","v2","v3","v4")], by=list(name=DF$name), min, na.rm = TRUE)
name v1 v2 v3 v4
1 Yemen 4 2 3 5
This is like the SQL SELECT name, min(v1) GROUP BY name
. The min
function is arbitrary, you could also use max
or mean
, all of them return the non-NA value from an NA and a non-NA value if na.rm = TRUE
.
(An SQL-like coalesce()
function would sound better if existed in R.)
However, you should check first if all non-NA values for a given name
is identical. For example, run the aggregate
both with min
and max
and compare, or run it with range
.
Finally, if you have many more variables than just v1-4, you could use DF[,!(names(DF) %in% c("code","name"))]
to define the columns.
Adding dplyr
& data.table
solutions for completeness
Using dplyr::coalesce()
library(dplyr)
sum_NA <- function(x) {if (all(is.na(x))) x[NA_integer_] else sum(x, na.rm = TRUE)}
df %>%
group_by(name) %>%
summarise_all(sum_NA)
#> # A tibble: 1 x 6
#> name code v1 v2 v3 v4
#> <fct> <dbl> <dbl> <dbl> <dbl> <dbl>
#> 1 Yemen 691 4 2 3 5
# Ref: https://stackoverflow.com/a/45515491
# Supply lists by splicing them into dots:
coalesce_by_column <- function(df) {
return(dplyr::coalesce(!!! as.list(df)))
}
df %>%
group_by(name) %>%
summarise_all(coalesce_by_column)
#> # A tibble: 1 x 6
#> name code v1 v2 v3 v4
#> <fct> <dbl> <dbl> <dbl> <dbl> <dbl>
#> 1 Yemen 345 4 2 3 5
Using data.table
# Ref: https://stackoverflow.com/q/28036294/
library(data.table)
setDT(df)[, lapply(.SD, na.omit), by = name]
#> name code v1 v2 v3 v4
#> 1: Yemen 345 4 2 3 5
#> 2: Yemen 346 4 2 3 5
setDT(df)[, code := NULL][, lapply(.SD, na.omit), by = name]
#> name v1 v2 v3 v4
#> 1: Yemen 4 2 3 5
setDT(df)[, code := NULL][, lapply(.SD, sum_NA), by = name]
#> name v1 v2 v3 v4
#> 1: Yemen 4 2 3 5
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