Making async for loops in Python

Question

The following code outputs as follows:

1 sec delay, print "1", 
1 sec delay, print "2", 
1 sec delay, print "1", 
1 sec delay, print "2"

How can it be modified to run like this:

1 sec delay, print "1", print "1",
1 sec delay, print "2", print "2"

I would like it to run so that both instances of the for loop begin executing at the same time. As each instance executes, they will encounter the first() function at the same time, then the second() function at the same time, thus printing in the order mentioned above.

Code:

import asyncio

async def first():
    await asyncio.sleep(1)
    return "1"

async def second():
    await asyncio.sleep(1)
    return "2"

async def main():     
    for i in range(2):
      result = await first()
      print(result)
      result2 = await second()
      print(result2)


loop = asyncio.get_event_loop()
loop.run_until_complete(main())

Answer 1

Looking at the desired output, it seems that the goal is to leave the individual iteration as it is - i.e. run first and second sequentially - but execute both loop iterations in parallel.

Assuming you only want to modify main(), it could be achieved like this:

async def main():
    async def one_iteration():
        result = await first()
        print(result)
        result2 = await second()
        print(result2)
    coros = [one_iteration() for _ in range(2)]
    await asyncio.gather(*coros)

Instead of iterating in sequence, the above creates a coroutine for each iteration task, and uses asyncio.gather to execute all the iterations in parallel.

Note that simply creating a coroutine doesn't start executing it, so a large number of coros won't block the event loop.