Makefile - remove ../ from path

Question

I have object files coming in with paths that might look like this:

 '../../src/foo/bar.c'

I'd like them to be output to

 'build/src/foo/bar.o'

Currently using:

 COBJS      :=  $(notdir $(CFILES))
 COBJS      :=  $(patsubst %,$(BUILD)%.o,$(COBJS))

I can achieve

 'build/bar.o'

This is problematic if any two library/project contains the same class name.

So the question is, how can one remove multiple '../' from a path in Make. I've attempted the obvious and naive approaches with no results.

Update, the following will match exactly ../../ and replace it with the rest. This is perfect except that it is specific to ../../. Just need to make it match any number of ../../

 COBJS      :=  $(CFILES:../../%=%)

Update,

SOLVED, just three reputation shy of posting my own answer.

 COBJS      :=  $(subst ../,,$(CFILES))

Answer 1

As posted in my original question and I forgot to eventually answer.

The solution for this and likely many other Make string replacement is as follows:

COBJS      :=  $(subst ../,,$(CFILES))

'subst' takes 3 parameters. $toMatch, $replaceWith, $string.

In this case $(CFILES) is the list of all .c files to compile. I replace '../' with nothing.