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Lookup table in Latex

I have a bunch of automatically generated LaTeX code with hypertargets of the form "functionname_2093840289fad1337", i.e the name of a function with a hash appended. I would like to refer to those functions from the rest of the document by only referring to the function name which I know is unique. I would like a lookup function something like this:

\hyperdyperlink{functionname}

that emits

\hyperlink{functionname_2093840289fad1337}{functionname}

Note that I can't calculate the hash but I'm prepared to write a table that maps each functionname to functionname+hash. What's the best way to write this kind of function?

like image 606
Laserallan Avatar asked Jun 08 '09 09:06

Laserallan


2 Answers

Does this work?

    \makeatletter
    \newcommand\hashlink[2]{%
      \@namedef{hashlink-#1}{#2}%
    }
    \newcommand\hyperdyperlink[1]{%
      \hyperlink
        {#1_\@nameuse{hashlink-#1}}
        {#1}%
    }
    \hashlink{functionname}{2093840289fad1337}
    \hyperdyperlink{functionname}
    \makeatother

(Untested.)


Later: To branch the code depending if you've defined the link target, you can write something like

    \newcommand\hyperdyperlink[1]{%
      \@ifundefined{hashlink-#1}{%
        [whatever else you want to do]
      }{%
        \hyperlink{#1_\@nameuse{hashlink-#1}}{#1}%
      }%
    }

(Update: oops; that was pretty broken as first posted, sorry. Now fixed, I hope.)

like image 155
Will Robertson Avatar answered Nov 15 '22 12:11

Will Robertson


Since the function names are unique, could you not define the hyperlink targets without the hash appended?

Alternatively, you could create a new LaTeX macro for each function. The code that generates the LaTeX code could do this by outputting code like this:

\newcommand{\linkFoo}{\hyperlink{foo_2093840289fad1337}{foo}}
\newcommand{\linkBar}{\hyperlink{bar_4323812312asf1342}{bar}}

Then use \linkFoo and friends in your hand-written part.

You could also implement a proper lookup table with TeX macros if you really wanted -- see this thread for an example -- but this solution is quite easy and simpler to understand (IMHO).

like image 32
Martin Geisler Avatar answered Nov 15 '22 10:11

Martin Geisler