LiteralExpression - ArgumentOutOfRangeException

Question

For the life of me, I cannot figure out why this line of code:

var literalExpressionSyntax = 
     Syntax.LiteralExpression(SyntaxKind.CharacterLiteralExpression);

throws an ArgumentOutOfRangeException under Roslyn CTP3.

Answer 1

The reason the second parameter is optional is that the text is implied for some SyntaxKind values. For example, if you pass SyntaxKind.TrueLiteral for the first argument, then you can omit the second one. However, when there is no reasonable default for the second parameter based on the first parameter, we throw the ArgumentOutOfRangeException.

In your example, you can create the expression with:

Syntax.LiteralExpression(SyntaxKind.CharacterLiteralExpression, Syntax.Literal('a'))

Answer 2

Shouldn't you supply the second argument, which is the actual literal.