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I need to operate on two separate infinite list of numbers, but could not find a way to generate, store and operate on it in python.
Can any one please suggest me a way to handle infinite Arithmetic Progession or any series and how to operate on them considering the fact the minimal use of memory and time.
Thanks every one for their suggestions in advance.
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Infinite lists, whose elements are evaluated upon demand, can be implemented using functions as data. The tail of a lazy list is a function that, if called, pro- duces another lazy list. A lazy list can be infinitely long and any finite number of its elements can be evaluated.
Lists do not have a built-in limit, but your computer hardware and the Jupyter kernel has a limit of available memory. If you need to work with large amount of data, use generators, and generator expressions. Do not put all the values in a list, but evaluate them one by one.
In Python, a list is created by placing elements inside square brackets [] , separated by commas. A list can have any number of items and they may be of different types (integer, float, string, etc.). A list can also have another list as an item.
To create a list of n placeholder elements, multiply the list of a single placeholder element with n . For example, use [None] * 5 to create a list [None, None, None, None, None] with five elements None . You can then overwrite some elements with index assignments.
You are looking for a python generator instead:
def infinitenumbers():
count = 0
while True:
yield count
count += 1
The itertools package comes with a pre-built count generator.
>>> import itertools
>>> c = itertools.count()
>>> next(c)
0
>>> next(c)
1
>>> for i in itertools.islice(c, 5):
... print i
...
2
3
4
5
6
This is where the iterator comes in. You can't have an infinite list of numbers, but you can have an infinite iterator.
import itertools
arithmetic_progression = itertools.count(start,step) #from the python docs
The docs for Python2 can be found here
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