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Haskell can this:
['a'..'z']
In Python:
map(chr, range(97, 123))
I feel Python is something verbose. Have Python another easy way like Haskell?
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1 General Approach for Python Alphabet. The ASCII value of A-Z lies in the range of 65-90, and the for a-z, the value is in the range 97 – 122. 2 Python Alphabet using list comprehension. ... 3 Python Alphabet using map function. ... 4 Importing the String Module. ...
If you prefer the alphabet list to be in uppercase, then you should use string.ascii_uppercase and reuse the code above and will produce the same output, but in uppercase format. range () is a function that outputs a series of numbers. You can specify when the function starts and stops with the first and second arguments.
In this tutorial, we want to store the English alphabet’s 26 lowercase characters in a Python list. The quickest way to solve this problem is by making use of the ASCII values of each character and using pre-existing functions in Python.
To create a list in Python, we use square brackets ( [] ). Here's what a list looks like: ListName = [ListItem, ListItem1, ListItem2, ListItem3, ...] Note that lists can have/store different data types. You can either store a particular data type or mix them. In the next section, you'll see how to add items to a list.
A slightly more readable version without importing anything
alphabet = [chr(i) for i in range(ord('a'), ord('z') + 1)]
Yes. from string import ascii_lowercase.
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