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Is there any clever in-built function or something that will return 1 for the min() example below? (I bet there is a solid reason for it not to return anything, but in my particular case I need it to disregard None values really bad!)
>>> max([None, 1,2]) 2 >>> min([None, 1,2]) >>> 
502
None is a valid element, but you can treat it like a stub or placeholder. So it counts as an element inside the list even if there is only a None .
The Python min() function returns the lowest value in a list of items. min() can be used to find the smallest number in a list or first string that would appear in the list if the list were ordered alphabetically.
Using min() and zip() In the below example we use the min() and zip(). Here the zip() function organizes the elements at the same index from multiple lists into a single list. Then we apply the min() function to the result of zip function using a for loop.
None is being returned
>>> print min([None, 1,2]) None >>> None < 1 True If you want to return 1 you have to filter the None away:
>>> L = [None, 1, 2] >>> min(x for x in L if x is not None) 1 If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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