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Inside a directory, how can I delete files that lack any of the words specified, so that only files that contain ALL the words are left? I tried to write a simple bash shell script using grep and rm commands, but I got lost. I am totally new to Linux, any help would be appreciated
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Highlight all the files you want to keep by clicking the first file type, hold down the Shift key, and click the last file. Once all the files you want to keep are highlighted, on the Home Tab, click Invert Selection to select all other files and folders.
To remove a directory and all its contents, including any subdirectories and files, use the rm command with the recursive option, -r . Directories that are removed with the rmdir command cannot be recovered, nor can directories and their contents removed with the rm -r command.
How about:
grep -L foo *.txt | xargs rm
grep -L bar *.txt | xargs rm
If a file does not contain foo, then the first line will remove it.
If a file does not contain bar, then the second line will remove it.
Only files containing both foo and bar should be left
-L, --files-without-match
Suppress normal output; instead print the name of each input
file from which no output would normally have been printed. The
scanning will stop on the first match.
See also @Mykola Golubyev's post for placing in a loop.
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