Print dates in date range linux

Question

I am new to linux. How can I print and store date in given date range.

For example I have startdate=2013-03-01 and enddate = 2013-03-25 ; I want to print all date in that range.

Thanks in advance

Answer 1

Another option is to use dateseq from dateutils (http://www.fresse.org/dateutils/#dateseq):

$ dateseq 2013-03-01 2013-03-25
2013-03-01
2013-03-02
2013-03-03
2013-03-04
2013-03-05
2013-03-06
2013-03-07
2013-03-08
2013-03-09
2013-03-10
2013-03-11
2013-03-12
2013-03-13
2013-03-14
2013-03-15
2013-03-16
2013-03-17
2013-03-18
2013-03-19
2013-03-20
2013-03-21
2013-03-22
2013-03-23
2013-03-24
2013-03-25

Answer 2

As long as the dates are in YYYY-MM-DD format, you can compare them lexicographically, and let date do the calendar arithmetic without converting to seconds first:

startdate=2013-03-15
enddate=2013-04-14

curr="$startdate"
while true; do
    echo "$curr"
    [ "$curr" \< "$enddate" ] || break
    curr=$( date +%Y-%m-%d --date "$curr +1 day" )
done

With [ ... ], you need to escape the < to avoid confusion with the input redirection operator.

This does have the wart of printing the start date if it is greater than the end date.