Linux: Calling a function within a case

Question

I am trying to set up a menu system where on selection it runs a function. In my case is runs the 'testfunc' function. However is it fails giving the error; testfunc: command not found.

My case statement looks like this;

case "$mainMenuInput" in
   1)testfunc ;;
esac

function testfunc{
    echo "This is a test"
}

Thanks in advance.

Answer 1

Shell scripts are executed statement at a time. The function is only known from the point you define it. You have to move it before the call.