Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

KnockoutJS ObservableArray data grouping

Tags:

knockout.js

Does KnockoutJS have a feature whereas I could take something like:

    var myArray = ko.observableArray([
      { name: "Jimmy", type: "Friend" },
      { name: "George", type: "Friend" },
      { name: "Zippy", type: "Enemy" }
    ]);

Then select distinct on the "type" field, producing a result which looks like this:

(pseudo code)
    var distinct = myArray.distinct('type')
      // Returns array of two arrays
      //  distinct[0] is an array of type=Friend
      //  distinct[1] is an array of type=Enemy 

I'm aware of ko.utils.arrayGetDistinctValues, but that doesn't exactly do what I want. I'm also aware that I could write a few loops using ko.utils.arrayGetDistinctValues to get what I want, I'm just wondering if there is something else baked into KnockoutJS that I'm overlooking.

like image 869
farina Avatar asked Mar 26 '12 18:03

farina


3 Answers

There is not anything else built into KO to make this any easier.

There are many ways that you could make this work. For example, you could extend observableArrays to have a distinct function. Then, you can just create your observableArray like:

this.people = ko.observableArray([
       new Person("Jimmy", "Friend"),
       new Person("George", "Friend"),
       new Person("Zippy", "Enemy")
]).distinct('type');

The distinct function might look like:

ko.observableArray.fn.distinct = function(prop) {
    var target = this;
    target.index = {};
    target.index[prop] = ko.observable({});    

    ko.computed(function() {
        //rebuild index
        var propIndex = {};

        ko.utils.arrayForEach(target(), function(item) {
            var key = ko.utils.unwrapObservable(item[prop]);
            if (key) {
                propIndex[key] = propIndex[key] || [];
                propIndex[key].push(item);            
            }
        });   

        target.index[prop](propIndex);
    });

    return target;
};    

It supports chaining so you could call distinct multiple times with different properties.

Sample here: http://jsfiddle.net/rniemeyer/mXVtN/

This does rebuild the index once on each change, so if you have a huge list of items, then you would want to potentially explore other ways (manual subscriptions) for adding/removing items from the "index" arrays.

like image 132
RP Niemeyer Avatar answered Nov 06 '22 01:11

RP Niemeyer


I have simplified RP Niemeyer's version in jsfiddle to do the same without using the distinct function. Please refer here: jsfiddle

<ul data-bind="foreach: choices">
<li>
    <h2 data-bind="text: $data"></h2>
    <ul data-bind="foreach: $root.people">
        <!-- ko if: $parent === type() -->
        <li data-bind="text: name"></li>
        <!-- /ko -->
    </ul>
    <hr/>
</li>

var Person = function(name, type) {
   this.name = ko.observable(name);
   this.type = ko.observable(type);    
}

var ViewModel = function() {
    var self = this; 
    this.choices = ["Friend", "Enemy", "Other" ];
    this.people = ko.observableArray([
           new Person("Jimmy", "Friend"),
           new Person("George", "Friend"),
           new Person("Zippy", "Enemy")
    ]);

    this.addPerson = function() {
        self.people.push(new Person("new", "Other"));
    };

    this.removePerson = function(person) {
      self.people.remove(person);  
    };
};


ko.applyBindings(new ViewModel());

Thanks Niemeyer.

like image 32
Govin Avatar answered Nov 06 '22 00:11

Govin


Just want to add to this that if you call this .distinct() method twice (like maybe from a computed observable), you'll get the indexes and associated computed function called twice - rinse and repeat and you've got a performance problem on your hands.

To sort this out, add this line near the top of the function:

if (target.index && target.index[prop]) return target; //Group by already set up, bail out.
like image 41
David Husselmann Avatar answered Nov 06 '22 00:11

David Husselmann