JsonResult return Json in ASP.NET CORE 2.1

Question

Controller that worked in ASP.NET Core 2.0:

[Produces("application/json")] [Route("api/[controller]")] [ApiController] public class GraficResourcesApiController : ControllerBase {         private readonly ApplicationDbContext _context;      public GraficResourcesApiController(ApplicationDbContext context)     {         _context = context;     }      [HttpGet]     public JsonResult GetGrafic(int ResourceId)     {         var sheduling = new List<Sheduling>();           var events = from e in _context.Grafic.Where(c=>c.ResourceId == ResourceId)                      select new                      {                          id = e.Id,                          title = e.Personals.Name,                          start = e.DateStart,                          end = e.DateStop,                          color = e.Personals.Color,                          personalId = e.PersonalId,                          description = e.ClientName                      };         var rows = events.ToArray();          return Json(rows);     } } 

in ASP.NET Core 2.1

return Json (rows); 

writes that Json does not exist in the current context. If we remove Json leaving simply

return rows; 

then writes that it was not possible to explicitly convert the type List () to JsonResult

How to convert to Json now?

Answer 1

In asp.net-core-2.1 ControllerBase does not have a Json(Object) method. However Controller does.

So either refactor the current controller to be derived from Controller

public class GraficResourcesApiController : Controller {     //... } 

to have access to the Controller.Json Method or you can initialize a new JsonResult yourself in the action

return new JsonResult(rows); 

which is basically what the method does internally in Controller

/// <summary> /// Creates a <see cref="JsonResult"/> object that serializes the specified <paramref name="data"/> object /// to JSON. /// </summary> /// <param name="data">The object to serialize.</param> /// <returns>The created <see cref="JsonResult"/> that serializes the specified <paramref name="data"/> /// to JSON format for the response.</returns> [NonAction] public virtual JsonResult Json(object data) {     return new JsonResult(data); }  /// <summary> /// Creates a <see cref="JsonResult"/> object that serializes the specified <paramref name="data"/> object /// to JSON. /// </summary> /// <param name="data">The object to serialize.</param> /// <param name="serializerSettings">The <see cref="JsonSerializerSettings"/> to be used by /// the formatter.</param> /// <returns>The created <see cref="JsonResult"/> that serializes the specified <paramref name="data"/> /// as JSON format for the response.</returns> /// <remarks>Callers should cache an instance of <see cref="JsonSerializerSettings"/> to avoid /// recreating cached data with each call.</remarks> [NonAction] public virtual JsonResult Json(object data, JsonSerializerSettings serializerSettings) {     if (serializerSettings == null)     {         throw new ArgumentNullException(nameof(serializerSettings));     }      return new JsonResult(data, serializerSettings); } 

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