How do I use the json_encode() function with MySQL query results? Do I need to iterate through the rows or can I just apply it to the entire results object?
$sth = mysqli_query($conn, "SELECT ...");
$rows = array();
while($r = mysqli_fetch_assoc($sth)) {
    $rows[] = $r;
}
print json_encode($rows);
The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here
NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php.
Try this, this will create your object properly
 $result = mysql_query("SELECT ...");
 $rows = array();
   while($r = mysql_fetch_assoc($result)) {
     $rows['object_name'][] = $r;
   }
 print json_encode($rows);
                        http://www.php.net/mysql_query says "mysql_query() returns a resource".
http://www.php.net/json_encode says it can encode any value "except a resource".
You need to iterate through and collect the database results in an array, then json_encode the array.
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