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JAXB unmarshalling without XmlRootElement annotation?

Tags:

java

jaxb

Is there any way we can un-marshall for a class without @XmlRootElement annotation? Or are we obligated to enter the annotation?

for example:

public class Customer {

    private String name;
    private int age;
    private int id;

    public String getName() {
        return name;
    }

    @XmlElement
    public void setName(String name) {
        this.name = name;
    }

    public int getAge() {
        return age;
    }

    @XmlElement
    public void setAge(int age) {
        this.age = age;
    }

    public int getId() {
        return id;
    }

    @XmlAttribute
    public void setId(int id) {
        this.id = id;
    }

}

and let the unmarshalling code for properly annotated class be like:

try {

        File file = new File("C:\\file.xml");
        JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);

        Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
        Customer customer = (Customer) jaxbUnmarshaller.unmarshal(file);
        System.out.println(customer);

      } catch (JAXBException e) {
        e.printStackTrace();
      }

leaving out the details.

like image 687
Kaleb Avatar asked Nov 20 '15 09:11

Kaleb


People also ask

What is JAXB unmarshalling?

The JAXB Unmarshaller interface is responsible for governing the process of deserializing the XML data to Java Objects. The unmarshalling to objects can be done to variety of input sources.

How do you Unmarshal string JAXB?

To unmarshal an xml string into a JAXB object, you will need to create an Unmarshaller from the JAXBContext, then call the unmarshal() method with a source/reader and the expected root object.

What is XmlRootElement?

@XmlRootElement is an annotation that people are used to using with JAXB (JSR-222). It's purpose is to uniquely associate a root element with a class. Since JAXB classes map to complex types, it is possible for a class to correspond to multiple root elements.


Video Answer


2 Answers

Following code is used to marshall and unmarshall withot @XmlRootElement

public static void main(String[] args) {

        try {

            StringWriter stringWriter = new StringWriter();

            Customer c = new Customer();
            c.setAge(1);
            c.setName("name");

            JAXBContext jaxbContext = JAXBContext.newInstance(Customer.class);

            Marshaller marshaller = jaxbContext.createMarshaller();
            marshaller.marshal(new JAXBElement<Customer>( new QName("", "Customer"), Customer.class, null, c), stringWriter);

            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            InputStream is = new ByteArrayInputStream(stringWriter.toString().getBytes());
            JAXBElement<Customer> customer = (JAXBElement<Customer>) jaxbUnmarshaller.unmarshal(new StreamSource(is),Customer.class);

            c = customer.getValue();

          } catch (JAXBException e) {
            e.printStackTrace();
          }

}

Above code works only if you adding @XmlAccessorType(XmlAccessType.PROPERTY) on Customer class, or make private all attributes.

like image 163
Xstian Avatar answered Oct 19 '22 10:10

Xstian


If you cannot add XmlRootElement to existing bean you can also create a holder class and mark it with annotation as XmlRootElement. Example below:-

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class CustomerHolder 
{
    private Customer cusotmer;

    public Customer getCusotmer() {
        return cusotmer;
}

    public void setCusotmer(Customer cusotmer) {
        this.cusotmer = cusotmer;
    }
}
like image 3
Abhishek K Avatar answered Oct 19 '22 09:10

Abhishek K