Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Javascript Uncaught ReferenceError while copying an object [duplicate]

Recently I ran into this weird thing in chrome console. Here I am intentionally assigning an undefined thing to a in order to throw an error.

let a = werwr // Uncaught ReferenceError: werwr is not defined

Then when I tried to assign something legit to a, this happened:

let a = "legit string"   // Uncaught SyntaxError: Identifier 'a' has already been declared

so I can't use "let" because a has already been declared. So I tried to reassign something else to the "already declared a"

a = "legit string"   //  Uncaught ReferenceError: a is not defined

So it seems like I can't reassign something else to a but at the same time, a has been declared so I can't use let again.

I understand the difference between declaring and assigning a variable. However here it seems that neither could be done again. Does this has something to do with the scope of "let" in console? Because the same thing totally works for "var"

var a = werwr 
// Uncaught ReferenceError: werwr is not defined

a = ”legit string“  
// ”legit string“

var a = "legit string" 
// Uncaught SyntaxError: Identifier 'a' has already been declared

Follow-up

There seem to be some difference between "manually" hoisting the let statement vs the implicit case.

throw new Error
let example = 5
// same errors as before

while in this case example can be reassigned again.

let example
throw new Error
example = 5
like image 619
whales Avatar asked Dec 21 '16 04:12

whales


People also ask

How can we copy object without mutating?

Similar to adding elements to arrays without mutating them, You can use the spread operator to copy the existing object into a new one, with an additional value. If a value already exists at the specified key, it will be overwritten.

How do you clone an object without references?

You can simply use copy = Object. create(originalObj); but you may want to use copy = JSON. parse(JSON. stringify(originalObj)); to avoid any reference in sub objects (Deep Copy).

How do you clone an object?

To clone an object, use the Object class's clone() method. It is the quickest way to duplicate an array. The class whose object clone we wish to generate must implement the Cloneable interface. If the Cloneable interface is not implemented, the clone() function throws a CloneNotSupportedException .


2 Answers

This happens when you introduce the temporal dead zone to the global scope. As you might know, let declarations are hoisted but left uninitialised. Due to control flow, it can happen that a variable is never initialised:

function …() {
    if (false)
        example; // would throw a ReferenceError if it was evaluated
    … // do something
    if (true)
        return; // stop!
    let example = 5; // never executed
}

This is fine in a function scope. Maybe something went wrong, maybe the variable wasn't needed at all - in the next call, a new scope with a new variable will be created.

A similar thing can happen in the global scope, when you throw an exception before the variable is initialised (only exceptions work here as a control flow construct, nothing else achieves the same effect).

throw new Error;
let example = 5;

In contrast to the function scope, it does matter here that the variable stays uninitialised. The global scope lasts forever, and the variable is eternally dead. It was not and will never be initialised, and lexical variables cannot be re-declared (which helps preventing mistakes).

This was discussed on es-discuss, but deemed irrelevant. If top-level <script> execution throws an error, you have bigger problems than uninitialised variables. There is no path to recover. If you need one (e.g. by trying to re-declare it in successive scripts), you have to use var anyway.

That you have the same problem in the devtools console is a bit of a nuisance, but could be solved for the console as a special scope.

like image 113
Bergi Avatar answered Nov 13 '22 19:11

Bergi


You should know about hoisting in JS. Basically, a declaration like this let a = werwr;

is interpreted as let a; a = werwr;

And that why a is already declared when you run your second line of code.

UPDATE

So, there is a NOTE in ES specs https://tc39.github.io/ecma262/#prod-LetOrConst

let and const declarations define variables that are scoped to the running execution context's LexicalEnvironment. The variables are created when their containing Lexical Environment is instantiated but may not be accessed in any way until the variable's LexicalBinding is evaluated. A variable defined by a LexicalBinding with an Initializer is assigned the value of its Initializer's AssignmentExpression when the LexicalBinding is evaluated, not when the variable is created. If a LexicalBinding in a let declaration does not have an Initializer the variable is assigned the value undefined when the LexicalBinding is evaluated.

...

"but may not be accessed in any way until the variable's LexicalBinding is evaluated" means that, the declaration must be successfully completed before you can access the variable (either getting value, assigning value, or doing typeof, or event delete);

In your case, the variable's LexicalBinding is interupted by the exception.

let a = werwr // Uncaught ReferenceError: werwr is not defined

Please follow the link and read more about that. If you find a way to recover varaible a, please tell me. Thanks, today I found out something new about Javascript.

like image 34
vothaison Avatar answered Nov 13 '22 17:11

vothaison