Java Jar file: use resource errors: URI is not hierarchical

Question

I have deployed my app to jar file. When I need to copy data from one file of resource to outside of jar file, I do this code:

URL resourceUrl = getClass().getResource("/resource/data.sav"); File src = new File(resourceUrl.toURI()); //ERROR HERE File dst = new File(CurrentPath()+"data.sav");  //CurrentPath: path of jar file don't include jar file name FileInputStream in = new FileInputStream(src); FileOutputStream out = new FileOutputStream(dst);  // some excute code here 

The error I have met is: URI is not hierarchical. this error I don't meet when run in IDE.

If I change above code as some help on other post on StackOverFlow:

InputStream in = Model.class.getClassLoader().getResourceAsStream("/resource/data.sav"); File dst = new File(CurrentPath() + "data.sav"); FileOutputStream out = new FileOutputStream(dst); //.... byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { //NULL POINTER EXCEPTION   //.... } 

Answer 1

You cannot do this

File src = new File(resourceUrl.toURI()); //ERROR HERE 

it is not a file! When you run from the ide you don't have any error, because you don't run a jar file. In the IDE classes and resources are extracted on the file system.

But you can open an InputStream in this way:

InputStream in = Model.class.getClassLoader().getResourceAsStream("/data.sav"); 

Remove "/resource". Generally the IDEs separates on file system classes and resources. But when the jar is created they are put all together. So the folder level "/resource" is used only for classes and resources separation.

When you get a resource from classloader you have to specify the path that the resource has inside the jar, that is the real package hierarchy.