What's the data structure in Java that has the fastest operation for contains() ?
e.g. i have a set of numbers { 1, 7, 12, 14, 20... }
Given another arbitrary number x, what's the fastest way (on average) to generate the boolean value of whether x is contained in the set or not? The probability for !contains() is about 5x higher.
Do all the map structures provide o(1) operation? Is HashSet the fastest way to go?
1- in current scenario, if concurrent users are not a concern then you can easily go for arraylist as its faster simpler data structure else if concurrent users are the concern then you can easily go for vector to store your events.
Arrays. An array is the simplest and most widely used data structure. Other data structures like stacks and queues are derived from arrays.
The best data structure I can think is of using the TreeSet. Here is the code, how you should define the structure. One more info- Use hashcode method of your URL class as hashcode of your url. This is how you define URLComparator class.
look at set (Hashset, enumset) and hash (HashMap,linkedhash...,idnetityhash..) based implementations. they have O(1) for contains()
This cheatsheet is of great help.
For your particular case of numbers with a relatively high density I'd use a BitSet, it will be faster and much smaller than a hash set.
The only data structure faster than HashSet is likely to be TIntHashSet from Trove4J. This uses primitives avoiding the need to use Integer Objects.
If the number of integers is small, you can create a boolean[] where each value present is turned into a "true". This will be O(1). Note: HashSet is not guarenteed to be O(1) and is more likely to be O(log(log(N))).
You will only get O(1) for an ideal hash distribution. However, it is more likely you will get collisions of hashed buckets and some lookups will need to check more than one value.
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