Why does the code below throw a java number format exception?
BigDecimal d = new BigDecimal("10934,375");
Yes, the BigDecimal
class does not take any Locale
into account in its constructor that takes a String
, as can be read in the Javadoc of this constructor:
the fraction consists of a decimal point followed by zero or more decimal digits.
If you want to parse according to a different Locale
, one that uses the comma as decimals separator, you need to use java.text.DecimalFormat
with a specific Locale
.
Example:
DecimalFormat fmt = new DecimalFormat("0.0", new DecimalFormatSymbols(Locale.GERMAN));
fmt.setParseBigDecimal(true);
BigDecimal n = (BigDecimal) fmt.parse("10934,375");
Note: you need to get an instance of DecimalFormat
(a subclass of NumberFormat
) to be able to call the method setParseBigDecimal
. Otherwise it returns a Double
instead, which is a binary floating point number, and binary floating point numbers cannot accurately represent many decimal fractions. So that would cause a loss of accuracy in many cases.
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