I'm trying to write a method to do a caesar shift on a string of text in the MIPS assembly language. My encryption method is as follows:
encryptMessage:
la $s0, message #s0 will hold message that will be iterated through
lw $t1, key #s1 will hold the key to shift by
li $t0, 0 #t0 will be iterator, starting at 0
encryptionLoop:
add $s1, $s0, $t0 #$s1 = message[i]
lb $s2, 0($s1) #Loading char to shift into $s2
beq $s2, $zero, exit #Breaking the loop if we've reached the end: http://stackoverflow.com/questions/12739463/how-to-iterate-a-string-in-mips-assembly
add $s2, $s2, $t1 #Shifting the character by the key amount
la $s1, ($s2) #Changing the character in message to the shifted character
addi $t0, $t0, 1 #i++
j encryptionLoop #Going back to the beginning of the loop
However, in the exit method where I print out the supposedly encrypted message, it just prints out the message as it was originally entered. My code isn't "remembering" that I changed the characters and I can't figure out how to get it to remember. I suspect this line
la $s1, ($s2) #Changing the character in message to the shifted character
has something to do with it but I don't know how to fix it.
Figured it out. That line I suspected should have been
sb $s2 ($s1)
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