Is there way to check if shell script is executed with -x flag

Question

I am trying to check in the script, that if that script is executed with -x flag which is for the debugging for shell scripts. Is there any way to check that in script itself that -x is set. I want to conditionally check that and do something if that is set.

Answer 1

Use:

if [[ $- == *x* ]]; then
  echo "debug"
else
  echo "not debug"
fi

From Bash manual:

($-, a hyphen.) Expands to the current option flags as specified upon invocation, by the set builtin command, or those set by the shell itself (such as the -i option).

Answer 2

The portable way to do this (without bashisms like [[ ]]) would be

case $- in
(*x*) echo "under set -x"
esac

Answer 3

You can trap the DEBUG signal, like so:

trap "do_this_if_it_is_being_debugged" DEBUG

function do_this_if_it_is_being_debugged() {
...
}

Note this needs to be executed before the set -x is being executed