Check if nth bit is set in bash

Question

I'm wondering if there's a way to replace the if statement with something that checks whether $2 has the 7th bit set to 1?

cat $file | awk '{if ($2 == 87) print $1; else {}}' > out.txt"

For instance, 93 should print something whereas 128 should not.

Answer 1

bash has bitwise operators

Test 7th bit:

$ echo $(((93 & 0x40) != 0))
1

$ echo $(((128 & 0x40) != 0))
0

See also the bash documentation

Though if you're parsing the values out of a file, you're probably better off continuing to use awk, as the answer of @RakholiyaJenish