Is there any way to get char by auto type deduction using decimal ASCII Code?

Question

For example 'a' has ASCII code 97 and we could use

char ch = 'a'; 

or

char ch = 97; 

With auto we could write

auto ch = 'a'; 

for the first case, but how to get char variable by numerical ascii code during deduction?

This doesn't work for me:

auto ch = '\97'; 

Answer 1

You have to use octal or hex value for escape sequence

auto ch  = '\141'; auto ch2 = '\x61'; 

For more info https://en.cppreference.com/w/cpp/language/escape

If you want to use decimal values, you have two options:

1. Cast to char

   auto ch = static_cast<char>(97); 

2. User-defined literals

   char operator "" _ch(unsigned long num) {      return static_cast<char>(num); } //... auto ch = 97_ch; 

Answer 2

There's no decimal escape, but you can use hexadecimal: '\x61', or octal, '\141'.
If you really need decimal, you need to cast; char{97}.