I have a list l
l = ['a','a','{','b','a','{','a','}','}','a']
I want to turn this list into the list below.
print(new_l)
# ['a','a',['{','b','a',['{','a','}'],'}'],'a']
So, basically, everything inside curly braces, including the bracces themselves should be inside a list nestled inside the original list.
Edit: Thank you all for the wonderful answers. Now, what I want the nestled lists to include the element before '{' as well? I know I should have mentioned this initially, but forgot about this requirement.
print(new_l)
# ['a',['a','{','b',['a','{','a','}'],'}'],'a']
Try this
import json
def add_nested_lists(l):
ltemp = '['
last_element = ''
n = len(l)
for i in range(0, n):
element = l[i]
if element == '{':
if l[i-1] == "{":
last_element = '"{", '
ltemp = ltemp[0:len(ltemp) - len(last_element)]
ltemp += '[' + last_element + '"' + element + '", '
last_element = '[' + last_element + '"' + element + '", '
else:
ltemp = ltemp[0:len(ltemp) - len(last_element)]
ltemp += '[' + last_element + '"' + element + '", '
last_element = '[' + last_element + '"' + element + '", '
elif element == "}":
if i == n - 1:
ltemp += '"' + element + '"]' + ']'
last_element = '"' + element + '"]' + ']'
else:
ltemp += '"' + element + '"]' + ', '
last_element = '"' + element + '"]' + ', '
else:
if i == 0 or i != n - 1: # first element or middle elements
ltemp += '"' + element + '", '
last_element = '"' + element + '", '
elif i == n - 1: # last element
ltemp += '"' + element + '"]'
last_element = '"' + element + '"]'
print(ltemp)
ltemp = json.loads(ltemp)
return ltemp
l = ['a','a','{','{','b','a','{','a','}','}','a','}']
print(type(l), add_nested_lists(l))
Output
<class 'list'> ['a', ['a', ['{', '{', 'b', ['a', '{', 'a', '}'], '}'], 'a', '}']]
And if you can and want more efficiency then try to make string instead of list 'l' as following
import json
l = '['
last_element = ''
is_last_element_is_curly = False
def add(element, position='m'): # m - middle element
global l, last_element, is_last_element_is_curly
if element == '{':
if is_last_element_is_curly:
last_element = '"{", '
l = l[0:len(l) - len(last_element)]
l += '[' + last_element + '"' + element + '", '
last_element = '[' + last_element + '"' + element + '", '
else:
l = l[0:len(l) - len(last_element)]
l += '[' + last_element + '"' + element + '", '
last_element = '[' + last_element + '"' + element + '", '
is_last_element_is_curly = True
elif element == "}":
if position == 'l':
l += '"' + element + '"]' + ']'
last_element = '"' + element + '"]' + ']'
else:
l += '"' + element + '"]' + ', '
last_element = '"' + element + '"]' + ', '
is_last_element_is_curly = False
else:
if position == 'f' or position == 'm': # f - first element or m - middle element
postfix = '", '
l += '"' + element + '", '
last_element = '"' + element + '", '
elif position == 'l': # l - last element
l += '"' + element + '"]'
last_element = '"' + element + '"]'
is_last_element_is_curly = False
#Do you stuff here and add elements to string 'l'
ltemp = ['a','a','{','{','b','a','{','a','}','}','a','}']
add(ltemp[0], position="f")
for i in range(1,len(ltemp) - 1):
add(ltemp[i])
add(ltemp[i + 1], position="l")
print(l)
#After that it will become very efficient
l = json.loads(l)
print(type(l),l)
Look into pyparsing
.
from pyparsing import nestedExpr
l = ['a','a','{','b','a','{','a','}','}','a']
l.insert(0, "{")
l.insert(len(l), "}")
print(nestedExpr('{','}').parseString(" ".join(l)).asList())
Will output:
[['a', 'a', ['b', 'a', ['a']], 'a']]
Which is not the exact output you are looking for, but perhaps a start. From here you can just access each nested list and add {
and }
to them.
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