Is there a better way to find anagrams using SQL?

Question

Given the following database table:

WORDS
 alphagram....varchar(15)
 word.........varchar(15) PK
 length.......int

Where:

• 'alphagram' is the letters of a word in alphabetical order (e.g. AEINNRTT is the alphagram of INTRANET)
• the primary key is 'word', and there are indexes on alphagram and length

I've found a way to find the anagrams of a given string of letters via SQL. For example, to find the anagrams of AEINNRTT this will work:

select alphagram, word, definition
from words
where length = 8
and alphagram like '%A%' 
and alphagram like '%E%' 
and alphagram like '%I%'
and alphagram like '%NN%' 
and alphagram like '%R%' 
and alphagram like '%TT%'

That will return 1 row (for INTRANET)

And if I wanted to include a known number of wildcards, for example, how many words are with INTRANET + a blank (wildcard) I just have to change the 'length' to the total number of letters + number of wild cards

e.g.

select alphagram, word, definition
from words
where length = 9
and alphagram like '%A%' 
and alphagram like '%E%' 
and alphagram like '%I%'
and alphagram like '%NN%' 
and alphagram like '%R%' 
and alphagram like '%TT%'

...will return 8 rows (ENTERTAIN, INSTANTER, INTEGRANT, INTRANETS, ITINERANT, NATTERING, RATTENING, and TRANSIENT)

My question is this: is there a more efficient way of doing this via SQL only?

This works pretty fast in SQLServer but pretty slow in SqlLite. I realise that the %xxx% searches are not fast.

Answer 1

You could create a kind of index column for each entry that has all the letters of the word in alphabetical order and then compare these. Each anagram will have the same index value.