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Is the typedef-name optional in a typedef declaration?

Tags:

c++

c

typedef

I was quite surprised when I saw the following code compile without errors or warnings in g++-4.2:

typedef enum test { one }; 

My assumption was that if you used the typedef keyword it would require an extra identifier as in:

typedef enum test { one } test; 

As already mentioned, g++-4.2 accepts it without even a warning. Clang++ 3.0 warns "warning: typedef requires a name", similarly Comeau warns "warning: declaration requires a typedef name", and g++-4.6 informs: "warning: 'typedef' was ignored in this declaration".

I have not been able to identify where in the standard this is allowed, and I find it slightly confusing that two of the compilers warn that it is required, shouldn't it be an error if the typedef-name is required but not present?

UPDATE: I have checked in C with the same compilers. Clang and comeau yield the same output, gcc gives a warning: "warning: useless storage class specifier in empty declaration", which seems even more confusing.

UPDATE: I have checked removing the name of the enum and the results are the same:

typedef enum { one }; 

Similarly with a named struct:

typedef struct named { int x }; 

But not with an unnamed struct, in which case the code was rejected in g++ (4.2/4.6) with "error: missing type-name in typedef-declaration", gcc (4.2/4.6) gave a warning: "warning: unnamed struct/union that defines no instances", clang++ "warning: declaration does not declare anything", comeau "error: declaration requires a typedef name"

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David Rodríguez - dribeas Avatar asked Jun 19 '11 00:06

David Rodríguez - dribeas


People also ask

What is a typedef declaration?

A typedef declaration is a declaration with typedef as the storage class. The declarator becomes a new type. You can use typedef declarations to construct shorter or more meaningful names for types already defined by C or for types that you have declared.

What is the typedef declaration give suitable example?

Formally, if the typedef declaration defines an unnamed class or enum, the first typedef-name declared by the declaration to be that class type or enum type is used to denote the class type or enum type for linkage purposes only. For example, in typedef struct { /* ... */ } S;, S is a typedef-name for linkage purposes.

What is the scope of a typedef?

A typedef is scoped exactly as the object declaration would have been, so it can be file scoped or local to a block or (in C++) to a namespace or class.

Does typedef create a new type?

However, the authoritative C/C++ reference website cplusplus says "typedef does not create different types.


2 Answers

It is a degenerate syntax that is allowed but provides no benefit. Most modern compilers can be provoked into emitting a warning about it; by default, they may not. Without the typedef name, the keyword typedef is superfluous; in your example, it is completely equivalent to:

enum test { one }; 

Another place where it can occur is with a structure:

typedef struct SomeThing { int whatever; }; 

This is equivalent to:

struct SomeThing { int whatever; }; 

Note that typedef is officially (or syntactically) a 'storage class specifier', like static, extern, auto and register.


C Standard

In ISO/IEC 9899:1999 (that's the C standard), we find:

§6.7 Declarations

Syntax

declaration:

declaration-specifiers init-declarator-listopt;

declaration-specifiers:

storage-class-specifier declaration-specifiersopt

type-specifier declaration-specifiersopt

type-qualifier declaration-specifiersopt

function-specifier declaration-specifiersopt

init-declarator-list:

init-declarator

init-declarator-list , init-declarator

init-declarator:

declarator

declarator = initializer

And (as requested):

§6.7.1 Storage-class specifiers

Syntax

storage-class-specifier:

typedef

extern

static

auto

register

If you track through that syntax, there are a lot of degenerate possibilities, and what you showed is just one of the many.


C++ Standard

It is possible that C++ has different rules.

In ISO/IEC 14882:1998 (the original C++ standard), we find in §7.1.1 'Storage class specifiers' that C++ does not treat typedef as a storage class; the list adds mutable and excludes typedef. So, the grammatical specification of typedef in C++ is definitely different from the C specification.

§7 Declarations

Declarations specify how names are to be interpreted. Declarations have the form

declaration-seq:

declaration

declaration-seq declaration

declaration:

block-declaration

function-definition

template-declaration

explicit-instantiation

explicit-specialization

linkage-specification

namespace-definition

block-declaration:

simple-declaration

asm-definition

namespace-alias-definition

using-declaration

using-directive

simple-declaration:

decl-specifier-seqopt init-declarator-listopt ;

...

¶5 If the decl-specifier-seq contains the typedef specifier, the declaration is called a typedef declaration and the name of each init-declarator is declared to be a typedef-name, synonymous with its associated type (7.1.3).

§7.1 Specifiers [dcl.spec]

The specifiers that can be used in a declaration are

decl-specifier:

storage-class-specifier

type-specifier

function-specifier

friend

typedef

decl-specifier-seq:

decl-specifier-seqopt

decl-specifier

§7.1.1 Storage class specifiers [dcl.stc]

storage-class-specifier:

auto

register

static

extern

mutable

§7.1.2 Function specifiers [dcl.fct.spec]

function-specifier:

inline

virtual

explicit

§7.1.3 The typedef specifier [dcl.typedef]

Declarations containing the decl-specifier typedef declare identifiers that can be used later for naming fundamental (3.9.1) or compound (3.9.2) types. The typedef specifier shall not be used in a function-definition (8.4), and it shall not be combined in a decl-specifier-seq with any other kind of specifier except a type-specifier.

typedef-name:

identifier

...

In a given scope, a typedef specifier can be used to redefine the name of any type declared in that scope to refer to the type to which it already refers. [Example:

typedef struct s { /* ... */ } s; typedef int I; typedef int I; typedef I I; 

—end example]

§7.1.4 The friend specifier [dcl.friend]

The friend specifier is used to specify access to class members; see 11.4.

§7.1.5 Type specifiers [dcl.type]

type-specifier:

simple-type-specifier

class-specifier

enum-specifier

elaborated-type-specifier

cv-qualifier


Since §7 ¶5 says that typedef names come from the init-declarator and the init-declarator-list is tagged 'opt', I think that means that the typedef name can be omitted in C++, just as in C.

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Jonathan Leffler Avatar answered Oct 03 '22 14:10

Jonathan Leffler


The only thing I could find was the following in the C++03 standard §7.1.3 [dcl.typedef] p1:

typedef-name:

  • identifier

A name declared with the typedef specifier becomes a typedef-name.

Notice the missing opt after identifier, which indicates, atleast to me, that an identifier is needed for the typedef-name. Strange that all tested compilers (silently) accept this.


Edit: After @Jonathan's answer, I found the following in the same standard as above:

decl-specifier:

  • storage-class-specifier
  • type-specifier
  • function-specifier
  • friend
  • typedef

As can be seen, it provides an extra case for typedef and the list on storage-class-specifiers confirms this:

storage-class-specifier:

  • auto
  • register
  • static
  • extern
  • mutable

So, we're just as clueless as before in the C++ case.

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Xeo Avatar answered Oct 03 '22 16:10

Xeo