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I started a new private project and decided to use more C++11/14 this time. So I also started using the new return syntax
auto functionName() -> returnType; It works for the most part very well, but now I needed some error handling and could not find out how to re-write stuff like this:
virtual const char* what() const noexcept override; with the new syntax. Are there some cases where the new syntax can not be used or am I only not clever enough to find the right order? For me it is important to keep things consistent, so I hope the problem is more on my side.
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The return statement terminates the execution of a function and returns control to the calling function. Execution resumes in the calling function at the point immediately following the call. A return statement can also return a value to the calling function.
this means pointer to the object, so *this is an object. So you are returning an object ie, *this returns a reference to the object.
The normal exit of program is represented by zero return value. If the code has errors, fault etc., it will be terminated by non-zero value. In C++ language, the main() function can be left without return value. By default, it will return zero.
The reason for the problem is that noexcept is part of the function declarator (and proposed to be part of the function type in C++17), while override is an (optionally used) identifier that is not part of the function declarator.
Hence, without use of override the declaration would be
virtual auto what() const noexcept -> const char *; and, since override must appear after this declaration, it will result in
virtual auto what() const noexcept -> const char * override; That said, rather than slavishly using C++11/C++14 features, pick the ones which best reflect your intent. There is not some rule that requires only use of C++11/C++14 features if there are older alternatives to achieve the same thing.
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