Is it possible to get the function name in function body? [duplicate]

Question

In BASH, is it possible to get the function name in function body? Taking following codes as example, I want to print the function name "Test" in its body, but "$0" seems to refer to the script name instead of the function name. So how to get the function name?

#!/bin/bash  function Test {     if [ $# -lt 1 ]     then         #   how to get the function name here?         echo "$0 num" 1>&2         exit 1     fi     local num="${1}"     echo "${num}" }  #   the correct function Test 100  #   missing argument, the function should exit with error Test  exit 0 

Answer 1

Try ${FUNCNAME[0]}. This array contains the current call stack. To quote the man page:

   FUNCNAME           An  array  variable  containing the names of all shell functions           currently in the execution call stack.  The element with index 0           is the name of any currently-executing shell function.  The bot‐           tom-most element is "main".  This variable exists  only  when  a           shell  function  is  executing.  Assignments to FUNCNAME have no           effect and return an error status.  If  FUNCNAME  is  unset,  it           loses its special properties, even if it is subsequently reset. 

Answer 2

The name of the function is in ${FUNCNAME[ 0 ]} FUNCNAME is an array containing all the names of the functions in the call stack, so:

 $ ./sample foo bar $ cat sample #!/bin/bash  foo() {         echo ${FUNCNAME[ 0 ]}  # prints 'foo'         echo ${FUNCNAME[ 1 ]}  # prints 'bar' } bar() { foo; } bar