I'm echoing some text in a bash script with a variable in it, and want to pad that variable so it will always have the appropriate ammount of spaces to the right to keep the rest of the text aligned.
Here's an example of what I want:
Echoing random number 1080 [ OK ] Echoing random number 443 [ OK ] Echoing random number 34842 [ OK ]
The numerical value would be of varying length (probably no longer than 5 or 6 digits).
I know that printf can do this and right align the variable by doing the following:
printf "Echoing random number %5s [ OK ]" $RAND_NUM
However, this would format the text like this:
Echoing random number 1080 [ OK ] Echoing random number 443 [ OK ] Echoing random number 34842 [ OK ]
And of course just echoing with spaces doens't work:
echo "Echoing random number ${RAND_NUM} [ OK ]"
Produces this:
Echoing random number 1080 [ OK ] Echoing random number 443 [ OK ] Echoing random number 34842 [ OK ]
Is there a way to print the text like my first example?
The operator "%" will try to remove the shortest text matching the pattern, while "%%" tries to do it with the longest text matching.
Print String in Bash To print a string in Bash, use echo command. Provide the string as command line argument to echo command.
Whitespace — this is a tab, newline, vertical tab, form feed, carriage return, or space. Bash uses whitespace to determine where words begin and end. The first word is the command name and additional words become arguments to that command.
Use -
to left align a field.
printf "Echoing random number %-5s [ OK ]" $RAND_NUM
Alternatively, if you're on a Red Hat Linux system there are predefined functions that will print out green OK and red FAILED prompts (the ones you see during bootup):
#!/bin/bash . /etc/init.d/functions echo -n "Frobbing widget:" frob_widget && echo_success || echo_failure echo
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