Is it possible to bind the second parameter of a lambda function?

Question

I'm new to C++11 lambdas and would like to turn a binary lambda into a unary one by binding its second parameter:

auto lambda1 = [] (int a, int b) { return a+b; };
auto lambda2 = std::bind2nd(lambda1, 5);

Compilation fails with

error: no type named 'first_argument_type' in 'struct main(int, char**)::<lambda(int, int)>'
     class binder2nd

[How] can this be done?

Answer 1

If you already employ lambda expressions, just use another one:

auto lambda2 = [&] (int i) {return lambda1(i, 5);};

Answer 2

#include <functional>

int main(int argc, char *argv[])
{
   auto lambda1 = [](int a, int b) { return a+b; };
   auto lambda2 = std::bind(lambda1, std::placeholders::_1, 5);
   //           ~~~~~~~^^^^~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^~~~
   return 0;
}

Demo

Also prefer to use std::bind over std::bind1st and std::bind2nd since both were deprecated in C++11 and are scheduled to be removed in C++17.